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Heat Energy Calculator (Q = mcΔT)

Computes thermal heat energy absorbed or released with specific heat capacity presets for common materials.

Thermal Energy Transfer (Specific Heat)

Calculate heat gained or lost by a substance: Q = m · c · ΔT

Q = mcΔT
Heating Scenarios:
Common Material Heat Capacities (c in J/kg·K):
Heat Flow & Temperature DifferenceΔT = +60.0 °C
20°→ 80°C
Total Thermal Energy Transfer (Q)
627,600 Joules (J)
🔥 Energy Gained / Absorbed (Endothermic)
Kilojoules627.600 kJ
Kilocalories150.00 kcal
BTU594.85 BTU
Watt-hours174.33 Wh
Step-by-Step Derivation
1. Formula: Sensible Heat Transfer Q = m · c · ΔT
2. Temperature Difference: ΔT = T_final - T_initial = 80°C - 20°C = 60.00 K (or °C)
3. Substitution: Q = (2.5 kg) × (4184 J/kg·K) × (60.00 K)
4. Heat Transferred: Q = 627600.00 Joules (J)
5. Thermal Direction: Heat is ABSORBED (+Q) by the substance (endothermic).
6. Equivalent Units: 627.600 kJ | 150.00 kcal | 594.85 BTU | 0.1743 kWh

What is Specific Heat?

Specific heat capacity is the amount of heat energy required to raise the temperature of 1 kg of a substance by 1 Kelvin.

Formula & Step-by-Step Calculation

Q = m × c × ΔT

Mass times specific heat times temperature difference.

Worked Step-by-Step Examples

Example 1

Heating 2.5 kg water from 20°C to 80°C

Solution: 627,600 Joules (627.6 kJ or 150 kcal)
• 2.5 × 4184 × (80 - 20) = 627,600 J

Common Real-World & Academic Use Cases

  • ✓ HVAC thermal heating load calculations
  • ✓ Boiler water heating power
  • ✓ Calorimetry chemical reaction heat

How to Use the Heat Energy Calculator (Q = mcΔT)

1

Enter Mass & Temp Change

Input kg and °C.

2

Select Specific Heat

Type or click material presets.

3

Inspect Heat Energy

Review Joules and kilocalories.

Frequently Asked Questions

Q: Why does water have such a high specific heat?

Strong intermolecular hydrogen bonds require large amounts of thermal energy to increase molecular kinetic motion.

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